In this article today we will cover Examples for Bar Bending Schedules of RCC Beam with Video Tutorial | Quantity Surveying | RCC Beam Reinforcement Calculation | BBS of RCC Beam | How to Calculate Bar Bending Schedule of Beam | Steel Calculation for RCC Beam | Reinforcement Calculations | Steel Quantity of RCC Beam | Bar Bending Schedule of RCC Slab
Bar bending schedule provides the reinforcement calculation for reinforced concrete beam. It provides details of reinforcement cutting length, type of bends and bend length.
We will take one example for reinforcement quantity calculations for a concrete beam.
Example No. 1: RCC Slab Reinforcement Calculation (Video Tutorial):
Example No. 2: RCC Beam Reinforcement Calculation (Written Below):
Consider
a RCC beam of clear length of 4m, 300mm wide by 450mm depth. It consists of 2-12
diameter bars at top, and 2-16 diameter and 1 – 12 diameter bars at the bottom.
Diameter of stirrup is 8mm spaced at 180mm center to center. Clear cover to
reinforcement provided is 40mm.
Fig: RCC Beam Cross-Section
Now we will calculate
the length of reinforcement based on the shapes of reinforcement required for
reinforced concrete beam in the above example.
We will start with
bottom reinforcement, B1.
Bar shape of B1 is as
shown below:
 |
Length
of B1 = clear distance between walls + 2 x width of walls – 2 x
bar cover + 2 x bend length
Bend
length = 6 x 16 = 96 consider as 100mm
Bend length is
calculated as 6 x diameter of bar for reinforcement conforming to IS: 1786-1961
Length of B1 = 4000 +
2 x 230 – 2 x 40 + 2 x100 = 4580mm
Length of bar B2 is
calculated based on shape of this bar. This bar bends up near the support as
shown below:
Length
of bar B2: A + B + C = 4000 + 2 x 230 – 2 x 40 + (1.414xH – H)
H = 450 – 2 x 40 – 2 x
12 – 2 x 12/2 = 334mm
B2 =
4000 + 2 x 230 – 2 x 40 + (1.414×334 – 334) = 4518.3 = 4520mm
Length
of Bar T1 = 4000 + 2 x 230 -2 x 40 = 4380mm
Length
of Stirrups S1:
Stirrups are spaced at
180mm center to center. Stirrups are provided between walls or support for a
beam.
No. of stirrups
required for given beam = 
Length
a = 450 – 2 x40 – 8 = 362mm
Length b = 300 – 2 x
40 – 8 = 212mm
Therefore length of 1
stirrup S1 = 2 x (212 + 362 + 90) = 1328 mm
Where 90mm is the
minimum hook length as per IS 2502 – Table – II.
Bar Bending Schedule for RCC
Beam (Table):
No.
|
Bar Mark
|
Bar dia (mm)
|
No. of bars
|
Length (mm)
|
Weight of bars (kg)
|
Bar Shape
|
1
|
B1
|
16
|
2
|
4580
|
14.5
|
 |
2
|
B2
|
12
|
1
|
4520
|
4.02
|
 |
3
|
T1
|
12
|
2
|
4380
|
7.80
|
 |
4
|
S1
|
8
|
24
|
1330
|
12.6
|
 |
Conclusion:
Full article on Examples for Bar Bending Schedules of RCC Beam with Video Tutorial | Quantity Surveying | RCC Beam Reinforcement Calculation | BBS of RCC Beam | How to Calculate Bar Bending Schedule of Beam | Steel Calculation for RCC Beam | Reinforcement Calculations | Steel Quantity of RCC Beam. Thank you for the full reading of this article in "QA QC Civil Engineering" platform in English. If you find this post helpful, then help others by sharing it on social media.
Full article on Examples for Bar Bending Schedules of RCC Beam with Video Tutorial | Quantity Surveying | RCC Beam Reinforcement Calculation | BBS of RCC Beam | How to Calculate Bar Bending Schedule of Beam | Steel Calculation for RCC Beam | Reinforcement Calculations | Steel Quantity of RCC Beam. Thank you for the full reading of this article in "QA QC Civil Engineering" platform in English. If you find this post helpful, then help others by sharing it on social media.
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